euclidean function造句
例句與造句
- A "'Euclidean domain "'is an integral domain which can be endowed with at least one Euclidean function.
- The third condition is a slight generalisation of condition ( EF1 ) of Euclidean functions, as defined in the Euclidean domain article.
- Many authors use other terms such as " degree function ", " valuation function ", " gauge function " or " norm function ", in place of " Euclidean function ".
- The definition is sometimes generalized by allowing the Euclidean function to take its values in any well-ordered set; this weakening does not affect the most important implications of the Euclidean property.
- Note that for a Euclidean function that is so established there need not exist an effective method to determine " q " and " r " in ( EF1 ).
- It's difficult to find euclidean function in a sentence. 用euclidean function造句挺難的
- If this norm satisfies the axioms of a Euclidean function then the number field " K " is called " norm-Euclidean " or simply " Euclidean ".
- If " f " is allowed to be any Euclidean function, then the list of possible " D " values for which the domain is Euclidean is not yet known.
- If the value of " x " can always be taken as 1 then " g " will in fact be a Euclidean function and " R " will therefore be a Euclidean domain.
- It is important to note that a particular Euclidean function " f " is " not " part of the structure of a Euclidean domain : in general, a Euclidean domain will admit many different Euclidean functions.
- It is important to note that a particular Euclidean function " f " is " not " part of the structure of a Euclidean domain : in general, a Euclidean domain will admit many different Euclidean functions.
- Some authors also require the domain of the Euclidean function to be the entire ring " R "; however this does not essentially affect the definition, since ( EF1 ) does not involve the value of " f ( 0 ) ".
- So, given an integral domain " R ", it is often very useful to know that " R " has a Euclidean function : in particular, this implies that " R " is a PID . However, if there is no " obvious " Euclidean function, then determining whether " R " is a PID is generally a much easier problem than determining whether it is a Euclidean domain.
- So, given an integral domain " R ", it is often very useful to know that " R " has a Euclidean function : in particular, this implies that " R " is a PID . However, if there is no " obvious " Euclidean function, then determining whether " R " is a PID is generally a much easier problem than determining whether it is a Euclidean domain.